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(-16x^2)+330x-121=0
We get rid of parentheses
-16x^2+330x-121=0
a = -16; b = 330; c = -121;
Δ = b2-4ac
Δ = 3302-4·(-16)·(-121)
Δ = 101156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{101156}=\sqrt{484*209}=\sqrt{484}*\sqrt{209}=22\sqrt{209}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(330)-22\sqrt{209}}{2*-16}=\frac{-330-22\sqrt{209}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(330)+22\sqrt{209}}{2*-16}=\frac{-330+22\sqrt{209}}{-32} $
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